x-4y=5;-x+2y=-3

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Solution for x-4y=5;-x+2y=-3 system of equations:


  • /| x-(4*y)-5 = 0| 2*y-x+3 = 0
  • We try to solve the equation: x-(4*y)-5 = 0
  • x-4*y-5 = 0 / - x-5
  • -4*y = -(x-5) / : -4
  • y = (-(x-5))/(-4)
  • y = (5-x)/(-4)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*((5-x)/(-4))-x+3 = 0| y = (5-x)/(-4)
  • (2*(5-x))/(-4)-x+3 = 0
  • 3-1/2*x-5/2 = 0
  • 1/2-1/2*x = 0
  • 1/2-1/2*x = 0 / - 1/2
  • -1/2*x = -1/2 / : -1/2
  • x = -1/2/(-1/2)
  • x = 1
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (5-x)/(-4):
  • y = (5-1)/(-4)
  • y = 4/(-4)
  • y = -1
  • We get a system of equations:
  • /| y = -1| x = 1

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