x+y=2;x-y=2

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2x+y=8
x+3y=14

Solution for x+y=2;x-y=2 system of equations:


  • /| x+y-2 = 0| x-y-2 = 0
  • We try to solve the equation: x+y-2 = 0
  • x+y-2 = 0 / - x-2
  • y = -(x-2)
  • y = 2-x
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| x+x-2-2 = 0| y = 2-x
  • 2*x-4 = 0 / + 4
  • 2*x = 4 / : 2
  • x = 4/2
  • x = 2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 2-x:
  • y = 2-2
  • y = 0
  • We get a system of equations:
  • /| y = 0| x = 2

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