# x+(3x+4)=12-(5x+1)

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## Solution for x+(3x+4)=12-(5x+1) equation:

x+(3x+4)=12-(5x+1)
We move all terms to the left:
x+(3x+4)-(12-(5x+1))=0
We get rid of parentheses
x+3x-(12-(5x+1))+4=0

We calculate terms in parentheses: -(12-(5x+1)), so:
12-(5x+1)
determiningTheFunctionDomain
-(5x+1)+12
We get rid of parentheses
-5x-1+12
We add all the numbers together, and all the variables
-5x+11
Back to the equation:
-(-5x+11)

We add all the numbers together, and all the variables
4x-(-5x+11)+4=0
We get rid of parentheses
4x+5x-11+4=0
We add all the numbers together, and all the variables
9x-7=0
We move all terms containing x to the left, all other terms to the right
9x=7
x=7/9
x=7/9

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