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x+(3x+4)=12-(5x+1)

We move all terms to the left:

x+(3x+4)-(12-(5x+1))=0

We get rid of parentheses

x+3x-(12-(5x+1))+4=0

We calculate terms in parentheses: -(12-(5x+1)), so:We add all the numbers together, and all the variables

12-(5x+1)

determiningTheFunctionDomain -(5x+1)+12

We get rid of parentheses

-5x-1+12

We add all the numbers together, and all the variables

-5x+11

Back to the equation:

-(-5x+11)

4x-(-5x+11)+4=0

We get rid of parentheses

4x+5x-11+4=0

We add all the numbers together, and all the variables

9x-7=0

We move all terms containing x to the left, all other terms to the right

9x=7

x=7/9

x=7/9

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