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sin((pi/3)*x) = 0

sin((pi/3)*x) = 0 <=> (pi/3)*x = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

(pi/3)*x-t_1 = 0

(pi/3)*x-t_1 = 0 / + t_1

(pi/3)*x = t_1 / : pi/3

x = t_1/(pi/3)

x = pi*k_1/(pi/3) i k_1 należy do I

x = pi*k_1/(pi/3)

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