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(ln(1-(10/x)))'The calculation above is a derivative of the function f (x)

(1/(1-(10/x)))*(1-(10/x))'

(1/(1-(10/x)))*((-(10/x))'+(1)')

(1/(1-(10/x)))*(((10)'*x-(10*(x)'))/(x^2)+(1)')

(1/(1-(10/x)))*((0*x-(10*(x)'))/(x^2)+(1)')

(1/(1-(10/x)))*((0*x-(10*1))/(x^2)+(1)')

(1/(1-(10/x)))*(10*x^-2+0)

(10*x^-2)/(1-(10*x^-1))

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