# Derivative of cos(4x)cos(2x)

## Derivative of cos(4x)cos(2x). Simple step by step solution, to learn. Simple, and easy to understand, so dont hesitate to use it as a solution of your homework.

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## Derivative of cos(4x)cos(2x):

(cos(4*x)*cos(2*x))'(cos(4*x))'*cos(2*x)+cos(4*x)*(cos(2*x))'cos(4*x)*(cos(2*x))'-sin(4*x)*(4*x)'*cos(2*x)cos(4*x)*(cos(2*x))'-sin(4*x)*((4)'*x+4*(x)')*cos(2*x)cos(4*x)*(cos(2*x))'-sin(4*x)*(0*x+4*(x)')*cos(2*x)cos(4*x)*(cos(2*x))'-sin(4*x)*(0*x+4*1)*cos(2*x)4*(-sin(4*x))*cos(2*x)+cos(4*x)*(cos(2*x))'cos(4*x)*(cos(2*x))'-4*sin(4*x)*cos(2*x)cos(4*x)*-sin(2*x)*(2*x)'-4*sin(4*x)*cos(2*x)cos(4*x)*-sin(2*x)*((2)'*x+2*(x)')-4*sin(4*x)*cos(2*x)cos(4*x)*-sin(2*x)*(0*x+2*(x)')-4*sin(4*x)*cos(2*x)cos(4*x)*-sin(2*x)*(0*x+2*1)-4*sin(4*x)*cos(2*x)cos(4*x)*2*(-sin(2*x))-4*sin(4*x)*cos(2*x)cos(4*x)*-2*sin(2*x)-4*sin(4*x)*cos(2*x)-4*sin(4*x)*cos(2*x)-(2*cos(4*x)*sin(2*x))`
The calculation above is a derivative of the function f (x)

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