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(2*ln(x+3))'The calculation above is a derivative of the function f (x)

(2)'*ln(x+3)+2*(ln(x+3))'

0*ln(x+3)+2*(ln(x+3))'

0*ln(x+3)+2*(1/(x+3))*(x+3)'

0*ln(x+3)+2*(1/(x+3))*((x)'+(3)')

0*ln(x+3)+2*((3)'+1)*(1/(x+3))

0*ln(x+3)+2*(0+1)*(1/(x+3))

0*ln(x+3)+2*(1/(x+3))

2/(x+3)

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