cos(2x)cos(x)=sin(4x)sin(x)

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Solution for cos(2x)cos(x)=sin(4x)sin(x) equation:


Simplifying
cos(2x) * cos(x) = sin(4x) * sin(x)
Remove parenthesis around (2x)
cos * 2x * cos(x) = sin(4x) * sin(x)
Reorder the terms for easier multiplication:
2cos * x * cos * x = sin(4x) * sin(x)
Multiply cos * x
2cosx * cos * x = sin(4x) * sin(x)
Multiply cosx * cos
2c2o2s2x * x = sin(4x) * sin(x)
Multiply c2o2s2x * x
2c2o2s2x2 = sin(4x) * sin(x)
Remove parenthesis around (4x)
2c2o2s2x2 = ins * 4x * sin(x)
Reorder the terms for easier multiplication:
2c2o2s2x2 = 4ins * x * ins * x
Multiply ins * x
2c2o2s2x2 = 4insx * ins * x
Multiply insx * ins
2c2o2s2x2 = 4i2n2s2x * x
Multiply i2n2s2x * x
2c2o2s2x2 = 4i2n2s2x2
Solving
2c2o2s2x2 = 4i2n2s2x2
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Divide each side by '2o2s2x2'.
c2 = 2i2n2o-2
Simplifying
c2 = 2i2n2o-2
Take the square root of each side:
c = {-1.414213562ino-1, 1.414213562ino-1}

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