(x-2)/(3)+(x-2)/(4) - adding of fractions

(x-2)/(3)+(x-2)/(4) - step by step solution for the given fractions. Adding of fractions, full explanation.

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    Solution for the given fractions

    $ \frac{(x-2)}{3 }+ \frac{(x-2)}{4 }=? $

    The common denominator of the two fractions is: 12

    $ \frac{(x-2)}{3 }= \frac{(4*(x-2))}{(3*4)} = \frac{(4*(x-2))}{12} $

    $ \frac{(x-2)}{4 }= \frac{(3*(x-2))}{(3*4)} = \frac{(3*(x-2))}{12} $

    Fractions adjusted to a common denominator

    $ \frac{(x-2)}{3 }+ \frac{(x-2)}{4 }= \frac{(4*(x-2))}{12 }+ \frac{(3*(x-2))}{12} $

    $ \frac{(4*(x-2))}{12 }+ \frac{(3*(x-2))}{12 }= \frac{(4*(x-2)+3*(x-2))}{12} $

    $ \frac{(4*(x-2)+3*(x-2))}{12 }= \frac{(4*(x-2)+3*(x-2))}{12} $

    $ $

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