(3x+14)/(5)+(x+54)/(7) - add fractions

(3x+14)/(5)+(x+54)/(7) - step by step solution for the given fractions. Add fractions, full explanation.

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    Solution for the given fractions

    • (3*x+14)/5 + (x+54)/7 = ?
    • The common denominator of the two fractions is: 35
    • (3*x+14)/5 = (7*(3*x+14))/(5*7) = (7*(3*x+14))/35
    • (x+54)/7 = (5*(x+54))/(5*7) = (5*(x+54))/35
    • Fractions adjusted to a common denominator
    • (3*x+14)/5 + (x+54)/7 = (7*(3*x+14))/35 + (5*(x+54))/35
    • (7*(3*x+14))/35 + (5*(x+54))/35 = (7*(3*x+14)+5*(x+54))/35
    • (7*(3*x+14)+5*(x+54))/35 = (7*(3*x+14)+5*(x+54))/35

    Solution for the given fractions

    $ \frac{(3*x+14)}{5 }+ \frac{(x+54)}{7 }=? $

    The common denominator of the two fractions is: 35

    $ \frac{(3*x+14)}{5 }= \frac{(7*(3*x+14))}{(5*7)} = \frac{(7*(3*x+14))}{35} $

    $ \frac{(x+54)}{7 }= \frac{(5*(x+54))}{(5*7)} = \frac{(5*(x+54))}{35} $

    Fractions adjusted to a common denominator

    $ \frac{(3*x+14)}{5 }+ \frac{(x+54)}{7 }= \frac{(7*(3*x+14))}{35 }+ \frac{(5*(x+54))}{35} $

    $ \frac{(7*(3*x+14))}{35 }+ \frac{(5*(x+54))}{35 }= \frac{(7*(3*x+14)+5*(x+54))}{35} $

    $ \frac{(7*(3*x+14)+5*(x+54))}{35 }= \frac{(7*(3*x+14)+5*(x+54))}{35} $

    $ $

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