# X2-280x+2400=0

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## Solution for X2-280x+2400=0 equation:

X2-280X+2400=0
We add all the numbers together, and all the variables
X^2-280X+2400=0
a = 1; b = -280; c = +2400;Δ = b2-4acΔ = -2802-4·1·2400Δ = 68800The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{68800}=\sqrt{1600*43}=\sqrt{1600}*\sqrt{43}=40\sqrt{43}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-280)-40\sqrt{43}}{2*1}=\frac{280-40\sqrt{43}}{2}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-280)+40\sqrt{43}}{2*1}=\frac{280+40\sqrt{43}}{2}$

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