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X2-280X+2400=0

We add all the numbers together, and all the variables

X^2-280X+2400=0

a = 1; b = -280; c = +2400;

Δ = b^{2}-4ac

Δ = -280^{2}-4·1·2400

Δ = 68800

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68800}=\sqrt{1600*43}=\sqrt{1600}*\sqrt{43}=40\sqrt{43}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-280)-40\sqrt{43}}{2*1}=\frac{280-40\sqrt{43}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-280)+40\sqrt{43}}{2*1}=\frac{280+40\sqrt{43}}{2} $

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