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Prime factorization of 56:

Prime factorization of 56 = 1×2×2×2×7= $ 1 × 2^3 × 7 $

By prime factorization of 56 we follow 5 simple steps:

1. We write number 56 above a 2-column table

2. We divide 56 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

56 | |

prime factors | number to factorize |

2 | 28 |

2 | 14 |

2 | 7 |

7 | 1 |

Prime factorization of 56 = 1×2×2×2×7= $ 1 × 2^3 × 7 $

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