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Prime factorization of 430:

Prime factorization of 430 = 1×2×5×43= $ 1 × 2 × 5 × 43 $

By prime factorization of 430 we follow 5 simple steps:

1. We write number 430 above a 2-column table

2. We divide 430 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

430 | |

prime factors | number to factorize |

2 | 215 |

5 | 43 |

43 | 1 |

Prime factorization of 430 = 1×2×5×43= $ 1 × 2 × 5 × 43 $

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