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Prime factorization of 212:

Prime factorization of 212 = 1×2×2×53= $ 1 × 2^2 × 53 $

By prime factorization of 212 we follow 5 simple steps:

1. We write number 212 above a 2-column table

2. We divide 212 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

212 | |

prime factors | number to factorize |

2 | 106 |

2 | 53 |

53 | 1 |

Prime factorization of 212 = 1×2×2×53= $ 1 × 2^2 × 53 $

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