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Prime factorization of 1200:

Prime factorization of 1200 = 1×2×2×2×2×3×5×5= $ 1 × 2^4 × 3 × 5^2 $

By prime factorization of 1200 we follow 5 simple steps:

1. We write number 1200 above a 2-column table

2. We divide 1200 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

1200 | |

prime factors | number to factorize |

2 | 600 |

2 | 300 |

2 | 150 |

2 | 75 |

3 | 25 |

5 | 5 |

5 | 1 |

Prime factorization of 1200 = 1×2×2×2×2×3×5×5= $ 1 × 2^4 × 3 × 5^2 $

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