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Factors of 735:

Factors of 735 = 1×3×5×7×7= $ 1 × 3 × 5 × 7^2 $

By prime factorization of 735 we follow 5 simple steps:

1. We write number 735 above a 2-column table

2. We divide 735 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

735 | |

prime factors | number to factorize |

3 | 245 |

5 | 49 |

7 | 7 |

7 | 1 |

Factors of 735 = 1×3×5×7×7= $ 1 × 3 × 5 × 7^2 $

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