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Factors of 612:

Factors of 612 = 1×2×2×3×3×17= $ 1 × 2^2 × 3^2 × 17 $

By prime factorization of 612 we follow 5 simple steps:

1. We write number 612 above a 2-column table

2. We divide 612 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

612 | |

prime factors | number to factorize |

2 | 306 |

2 | 153 |

3 | 51 |

3 | 17 |

17 | 1 |

Factors of 612 = 1×2×2×3×3×17= $ 1 × 2^2 × 3^2 × 17 $

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