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Factors of 540:

Factors of 540 = 1×2×2×3×3×3×5= $ 1 × 2^2 × 3^3 × 5 $

By prime factorization of 540 we follow 5 simple steps:

1. We write number 540 above a 2-column table

2. We divide 540 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

540 | |

prime factors | number to factorize |

2 | 270 |

2 | 135 |

3 | 45 |

3 | 15 |

3 | 5 |

5 | 1 |

Factors of 540 = 1×2×2×3×3×3×5= $ 1 × 2^2 × 3^3 × 5 $

| Prime factorization of 5 | | Prime factorization of 4 | | Factors of 42 | | Factors of 15 | | Factors of 10 | | Prime factorization of 59780 | | Prime factorization of 552 | | Factors of 260 | | Factors of 184 | | Factors of 84 | | Prime factorization of 121 | | Prime factorization of 6 | | Factors of 4734 | | Prime factorization of 457 | | Prime factorization of 84946 | | Factors of 3 | | Prime factorization of 3 | | Prime factorization of 123 | | Factors of 44 | | Factors of 233 | | Factors of 22 | | Factors of 125567 | | Factors of 39 | | Prime factorization of 125 |

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