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Factors of 536:

Factors of 536 = 1×2×2×2×67= $ 1 × 2^3 × 67 $

By prime factorization of 536 we follow 5 simple steps:

1. We write number 536 above a 2-column table

2. We divide 536 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

536 | |

prime factors | number to factorize |

2 | 268 |

2 | 134 |

2 | 67 |

67 | 1 |

Factors of 536 = 1×2×2×2×67= $ 1 × 2^3 × 67 $

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