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Factors of 441:

Factors of 441 = 1×3×3×7×7= $ 1 × 3^2 × 7^2 $

By prime factorization of 441 we follow 5 simple steps:

1. We write number 441 above a 2-column table

2. We divide 441 by the smallest possible prime factor

3. We write down on the left side of the table the prime factor and next number to factorize on the ride side

4. We continue to factor in this fashion (we deal with odd numbers by trying small prime factors)

5. We continue until we reach 1 on the ride side of the table

441 | |

prime factors | number to factorize |

3 | 147 |

3 | 49 |

7 | 7 |

7 | 1 |

Factors of 441 = 1×3×3×7×7= $ 1 × 3^2 × 7^2 $

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