A-(B-C)=(A-B)U(AnC)

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Solution for A-(B-C)=(A-B)U(AnC) equation:


Simplifying
A + -1(B + -1C) = (A + -1B) * U(AnC)
A + (B * -1 + -1C * -1) = (A + -1B) * U(AnC)
A + (-1B + 1C) = (A + -1B) * U(AnC)
Reorder the terms for easier multiplication:
A + -1B + 1C = U * nAC(A + -1B)
Multiply U * nAC
A + -1B + 1C = nACU(A + -1B)
A + -1B + 1C = (A * nACU + -1B * nACU)
Reorder the terms:
A + -1B + 1C = (-1nABCU + nA2CU)
A + -1B + 1C = (-1nABCU + nA2CU)
Solving
A + -1B + 1C = -1nABCU + nA2CU
Solving for variable 'A'.
Reorder the terms:
A + -1B + 1C + nABCU + -1nA2CU = -1nABCU + nABCU + nA2CU + -1nA2CU
Combine like terms: -1nABCU + nABCU = 0
A + -1B + 1C + nABCU + -1nA2CU = 0 + nA2CU + -1nA2CU
A + -1B + 1C + nABCU + -1nA2CU = nA2CU + -1nA2CU
Combine like terms: nA2CU + -1nA2CU = 0
A + -1B + 1C + nABCU + -1nA2CU = 0
The solution to this equation could not be determined.

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