# 9/5+3/5x=27/10+7/2x+1/2

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## Solution for 9/5+3/5x=27/10+7/2x+1/2 equation:

x in (-oo:+oo)(3/5)*x+9/5 = (7/2)*x+27/10+1/2 / - (7/2)*x+27/10+1/2(3/5)*x-((7/2)*x)+9/5-(27/10)-(1/2) = 0(3/5)*x+(-7/2)*x+9/5-27/10-1/2 = 0-29/10*x-7/5 = 0 / + 7/5-29/10*x = 7/5 / : -29/10x = 7/5/(-29/10)x = -14/29x = -14/29`

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