6(h+2)-4(h-1)=3(h+2)

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Solution for 6(h+2)-4(h-1)=3(h+2) equation:



6(h+2)-4(h-1)=3(h+2)
We move all terms to the left:
6(h+2)-4(h-1)-(3(h+2))=0
We multiply parentheses
6h-4h-(3(h+2))+12+4=0
We calculate terms in parentheses: -(3(h+2)), so:
3(h+2)
We multiply parentheses
3h+6
Back to the equation:
-(3h+6)
We add all the numbers together, and all the variables
2h-(3h+6)+16=0
We get rid of parentheses
2h-3h-6+16=0
We add all the numbers together, and all the variables
-1h+10=0
We move all terms containing h to the left, all other terms to the right
-h=-10
h=-10/-1
h=+10

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