4x+3y=40;x=2y-1

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for example:
2x+y=8
x+3y=14

Solution for 4x+3y=40;x=2y-1 system of equations:


  • /| 4*x+3*y-40 = 0| x-(2*y)+1 = 0
  • We try to solve the equation: 4*x+3*y-40 = 0
  • 4*x+3*y-40 = 0 / - 4*x-40
  • 3*y = -(4*x-40) / : 3
  • y = (-(4*x-40))/3
  • y = (40-(4*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| x-(2*((40-(4*x))/3))+1 = 0| y = (40-(4*x))/3
  • (-1*2*(40-4*x))/3+x+1 = 0
  • 11/3*x-80/3+1 = 0
  • 11/3*x-77/3 = 0
  • 11/3*x-77/3 = 0 / + 77/3
  • 11/3*x = 77/3 / : 11/3
  • x = 77/3/11/3
  • x = 7
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (40-(4*x))/3:
  • y = (40-(4*7))/3
  • y = (40-28)/3
  • y = 12/3
  • y = 4
  • We get a system of equations:
  • /| y = 4| x = 7

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