40-2x;X=3

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2x+y=8
x+3y=14

Solution for 40-2x;X=3 system of equations:


  • /| 40-(2*x) = 0| X-3 = 0
  • We try to solve the equation: X-3 = 0
  • X-3 = 0 / + 3
  • X = 3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 40-(2*x) = 0| X = 3
  • 40-2*x = 0 / - 40
  • -2*x = -40 / : -2
  • x = -40/(-2)
  • x = 20
  • We insert the solution into one of the initial equations of our system of equations
  • For X = 3:
  • X = 3
  • We get a system of equations:
  • /| X = 3| x = 20

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