3x+2y=0;12x+2=6y

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2x+y=8
x+3y=14

Solution for 3x+2y=0;12x+2=6y system of equations:


  • /| 3*x+2*y = 0| 12*x-(6*y)+2 = 0
  • We try to solve the equation: 3*x+2*y = 0
  • 3*x+2*y = 0 / - 3*x
  • 2*y = -(3*x) / : 2
  • y = (-(3*x))/2
  • y = (-3*x)/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 12*x-(6*((-3*x)/2))+2 = 0| y = (-3*x)/2
  • 21*x+2 = 0 / - 2
  • 21*x = -2 / : 21
  • x = -2/21
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (-3*x)/2:
  • y = (-3*(-2/21))/2
  • y = (2/21*3)/2
  • y = 2/7/2
  • y = 1/7
  • We get a system of equations:
  • /| y = 1/7| x = -2/21

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