2x-y=4;x+2y=2

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2x+y=8
x+3y=14

Solution for 2x-y=4;x+2y=2 system of equations:


  • /| 2*x-y-4 = 0| x+2*y-2 = 0
  • We try to solve the equation: 2*x-y-4 = 0
  • 2*x-y-4 = 0 / - 2*x-4
  • -y = -(2*x-4) / * -1
  • y = 2*x-4
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*(2*x-4)+x-2 = 0| y = 2*x-4
  • 2*(2*x-4)+x-2 = 0
  • 5*x-8-2 = 0
  • 5*x-10 = 0
  • 5*x-10 = 0 / + 10
  • 5*x = 10 / : 5
  • x = 10/5
  • x = 2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 2*x-4:
  • y = 2*2-4
  • y = 4-4
  • y = 0
  • We get a system of equations:
  • /| y = 0| x = 2

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