2x-3=y;y-2x=1

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2x+y=8
x+3y=14

Solution for 2x-3=y;y-2x=1 system of equations:


  • /| 2*x-y-3 = 0| y-(2*x)-1 = 0
  • We try to solve the equation: 2*x-y-3 = 0
  • 2*x-y-3 = 0 / - 2*x-3
  • -y = -(2*x-3) / * -1
  • y = 2*x-3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*x-(2*x)-3-1 = 0| y = 2*x-3
  • -4 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

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