2x-4y=3;10x-20y=6

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2x+y=8
x+3y=14

Solution for 2x-4y=3;10x-20y=6 system of equations:


  • /| 2*x-(4*y)-3 = 0| 10*x-(20*y)-6 = 0
  • We try to solve the equation: 2*x-(4*y)-3 = 0
  • 2*x-4*y-3 = 0 / - 2*x-3
  • -4*y = -(2*x-3) / : -4
  • y = (-(2*x-3))/(-4)
  • y = (3-(2*x))/(-4)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 10*x-(20*((3-(2*x))/(-4)))-6 = 0| y = (3-(2*x))/(-4)
  • (-1*20*(3-2*x))/(-4)+10*x-6 = 0
  • 15-6 = 0
  • 9 = 0
  • 9 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

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