27+3y-2=12y-11-3y

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Solution for 27+3y-2=12y-11-3y equation:



27+3y-2=12y-11-3y
We move all terms to the left:
27+3y-2-(12y-11-3y)=0
We add all the numbers together, and all the variables
3y-(9y-11)+27-2=0
We add all the numbers together, and all the variables
3y-(9y-11)+25=0
We get rid of parentheses
3y-9y+11+25=0
We add all the numbers together, and all the variables
-6y+36=0
We move all terms containing y to the left, all other terms to the right
-6y=-36
y=-36/-6
y=+6

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