1/3x+1/2y=1/6;1/3x+2y=5/3

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Solution for 1/3x+1/2y=1/6;1/3x+2y=5/3 system of equations:


  • /| (1/3)*x+(1/2)*y-(1/6) = 0| (1/3)*x+2*y-(5/3) = 0
  • We try to solve the equation: (1/3)*x+(1/2)*y-(1/6) = 0
  • 1/3*x+1/2*y-1/6 = 0 / - 1/3*x-1/6
  • 1/2*y = -(1/3*x-1/6) / : 1/2
  • y = (-(1/3*x-1/6))/1/2
  • y = 2*(1/6-(1/3*x))
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*2*(1/6-(1/3*x))+(1/3)*x-(5/3) = 0| y = 2*(1/6-(1/3*x))
  • 4*(1/6-1/3*x)+x/3-5/3 = 0
  • 2/3-x-5/3 = 0
  • -x-1 = 0
  • -x-1 = 0 / + 1
  • -x = 1 / * -1
  • x = -1
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 2*(1/6-(1/3*x)):
  • y = 2*(1/6-(-1*1/3))
  • y = 2*(1/6+1/3)
  • y = 1/2*2
  • y = 1
  • We get a system of equations:
  • /| y = 1| x = -1

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