1/2x+1/3y=-5/3;1/2x+4y=2

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Solution for 1/2x+1/3y=-5/3;1/2x+4y=2 system of equations:


  • /| (1/2)*x+(1/3)*y-(-5/3) = 0| (1/2)*x+4*y-2 = 0
  • We try to solve the equation: (1/2)*x+(1/3)*y-(-5/3) = 0
  • 1/2*x+1/3*y+5/3 = 0 / - 1/2*x+5/3
  • 1/3*y = -(1/2*x+5/3) / : 1/3
  • y = (-(1/2*x+5/3))/1/3
  • y = -3*(1/2*x+5/3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (1/2)*x-3*4*(1/2*x+5/3)-2 = 0| y = -3*(1/2*x+5/3)
  • x/2-12*(1/2*x+5/3)-2 = 0
  • -11/2*x-20-2 = 0
  • -11/2*x-22 = 0
  • -11/2*x-22 = 0 / + 22
  • -11/2*x = 22 / : -11/2
  • x = 22/(-11/2)
  • x = -4
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -3*(1/2*x+5/3):
  • y = -3*(5/3-4*1/2)
  • y = -3*(5/3-2)
  • y = -3*(-1/3)
  • y = 1/3*3
  • y = 1
  • We get a system of equations:
  • /| y = 1| x = -4

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