-8x-8=-40y;50y-10=10x

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2x+y=8
x+3y=14

Solution for -8x-8=-40y;50y-10=10x system of equations:


  • /| -8*x-(-40*y)-8 = 0| 50*y-(10*x)-10 = 0
  • We try to solve the equation: -8*x-(-40*y)-8 = 0
  • 40*y-8*x-8 = 0 / + -8*x-8
  • 40*y = -(-8*x-8) / : 40
  • y = (-(-8*x-8))/40
  • y = (8-(-8*x))/40
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 50*((8-(-8*x))/40)-(10*x)-10 = 0| y = (8-(-8*x))/40
  • (50*(8*x+8))/40-10*x-10 = 0
  • 10-10 = 0
  • 0 = 0
  • The system of equations has infinitely many solutions

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