(y2-4x)/7-4

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Solution for (y2-4x)/7-4 equation:


x in (-oo:+oo)

(y^2-(4*x))/7-4 = 0

(y^2-4*x)/7-4 = 0

(y^2-4*x)/7+(-4*7)/7 = 0

y^2-4*x-4*7 = 0

y^2-4*x-28 = 0

(y^2-4*x-28)/7 = 0

(y^2-4*x-28)/7 = 0 / * 7

y^2-4*x-28 = 0

y^2-4*x-28 = 0 / - y^2-28

-4*x = -(y^2-28) / : -4

x = (-(y^2-28))/(-4)

x = (28-y^2)/(-4)

x = (28-y^2)/(-4)

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