(n/n-3)+2=(3/2n-1)

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Solution for (n/n-3)+2=(3/2n-1) equation:



(n/n-3)+2=(3/2n-1)
We move all terms to the left:
(n/n-3)+2-((3/2n-1))=0
Domain of the equation: n-3)!=0
n∈R
Domain of the equation: 2n-1))!=0
n∈R
We get rid of parentheses
n/n-((3/2n-1))-3+2=0
Fractions to decimals
-((3/2n-1))-3+2+1=0
We multiply all the terms by the denominator
-((3-3*2n-1))+2*2n-1))+1*2n-1))=0
We calculate terms in parentheses: -((3-3*2n-1)), so:
(3-3*2n-1)
We add all the numbers together, and all the variables
(-3*2n+2)
We get rid of parentheses
-3*2n+2
Wy multiply elements
-6n+2
Back to the equation:
-(-6n+2)
Wy multiply elements
-(-6n+2)+4n-1))+1*2n-1))=0
We get rid of parentheses
6n+4n-1))+1*2n-1))-2=0
We add all the numbers together, and all the variables
10n-1))+1*2n-1))-2=0

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